[해결책] 기계재료학 (공업재료) 3판(Engineering Materials 1, Ashby 출판사 BH)
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작성일 20-05-09 22:39
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Download : [솔루션] 기계재료학 (공업재료) 3.pdf
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다. ln 2 ≈ 70
t
doubling times as 35, 23 and 18 years respectively.
Solutions to Examples
100
2.2. Principal conservation measures (see Section 2.7):
a starter filament, than an incandescent bulb!); lead in lead-acid batteries;
of surface coatings to prevent metal loss by corrosion (e.g. in motor cars).
rB
SOLUTIONS MANUAL
(b) The doubling time, tD, is calculated by setting Ct = t = 2C0, giving
re-designed to make recycling easier, and new recycling processes developed,
certain specific uses, most elements are not easily replaced. Examples: tungsten
many applications, substitutes are easily found at small penalty of cost. But in
rB
but development time is again important.
in cutting tools and lighting (a fluorescent tube contains more tungsten, as
Examples: aluminium for copper as a conductor; reinforced concrete for wood,
순서
[해결책] 기계재료학 (공업재료) 3판(Engineering Materials 1, Ashby 출판사 BH)
rA
설명
Recycling
The fraction of material recycled is obviously important. Products may be
platinum as a catalyst in chemical processing; etc. A long development time
Download : [솔루션] 기계재료학 (공업재료) 3.pdf( 66 )
(up to 25 years) may be needed to find a replacement.
Substitution of the values given for r in the table into this equation gives the
CB
2 Solutions Manual: Engineering Materials I
tD
stone or cast-iron in construction; plastics for glass or metals as containers. For
2.1. (a) For commodity A Pt = CA exp
![[솔루션] 기계재료학 (공업재료) 3-2312_01_.gif](http://www.happyreport.co.kr/prev/201112/%5B%EC%86%94%EB%A3%A8%EC%85%98%5D%20%EA%B8%B0%EA%B3%84%EC%9E%AC%EB%A3%8C%ED%95%99%20(%EA%B3%B5%EC%97%85%EC%9E%AC%EB%A3%8C)%203-2312_01_.gif)
![[솔루션] 기계재료학 (공업재료) 3-2312_02_.gif](http://www.happyreport.co.kr/prev/201112/%5B%EC%86%94%EB%A3%A8%EC%85%98%5D%20%EA%B8%B0%EA%B3%84%EC%9E%AC%EB%A3%8C%ED%95%99%20(%EA%B3%B5%EC%97%85%EC%9E%AC%EB%A3%8C)%203-2312_02_.gif)
![[솔루션] 기계재료학 (공업재료) 3-2312_03_.gif](http://www.happyreport.co.kr/prev/201112/%5B%EC%86%94%EB%A3%A8%EC%85%98%5D%20%EA%B8%B0%EA%B3%84%EC%9E%AC%EB%A3%8C%ED%95%99%20(%EA%B3%B5%EC%97%85%EC%9E%AC%EB%A3%8C)%203-2312_03_.gif)
![[솔루션] 기계재료학 (공업재료) 3-2312_04_.gif](http://www.happyreport.co.kr/prev/201112/%5B%EC%86%94%EB%A3%A8%EC%85%98%5D%20%EA%B8%B0%EA%B3%84%EC%9E%AC%EB%A3%8C%ED%95%99%20(%EA%B3%B5%EC%97%85%EC%9E%AC%EB%A3%8C)%203-2312_04_.gif)
![[솔루션] 기계재료학 (공업재료) 3-2312_05_.gif](http://www.happyreport.co.kr/prev/201112/%5B%EC%86%94%EB%A3%A8%EC%85%98%5D%20%EA%B8%B0%EA%B3%84%EC%9E%AC%EB%A3%8C%ED%95%99%20(%EA%B3%B5%EC%97%85%EC%9E%AC%EB%A3%8C)%203-2312_05_.gif)
in 201 years; polymers overtake steel in 55 years.
= 100
and for commodity B Qt = CB exp
기계, 공학, 과학, 연습문제, 솔루션, 재료
Engineering Materials I
where CA and CB are the current rates of consumption t = t0 and Pt and
1
−rA
r
t
레포트 > 공학,기술계열
An Introduction to Properties, Applications
and Design, 3rd edn
Substitution
CA
Design to use proportionally smaller amounts of scarce materials, for example,
100
ln
r
Qt are the values at t = t . Equating and solving for t gives
by building large plant (economy of scale); using high-strength materials; use
t = 100
More Economic Design
(c) Using the equation of Answer (a) we find that aluminium overtakes steel
(아래는 solution(솔루션) 표지 부분과 2장의 일부 연습문제 부분입니다.
